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Answer :
The specific heat capacity of the metal is approximately [tex]\( 0.382 \, \text{J/g°C} \).[/tex]
To find the specific heat capacity (c) of the metal, we can use the formula:
[tex]\[ q = mcΔT \]Where:- \( q \) is the heat added (in joules)- \( m \) is the mass of the metal (in grams)- \( c \) is the specific heat capacity of the metal (in J/g°C)- \( ΔT \) is the change in temperature (in °C)[/tex]
Given:
[tex]- \( m = 38.2 \, \text{g} \)- \( ΔT = 46.7 \, \text{°C} - 15.4 \, \text{°C} = 31.3 \, \text{°C} \)- \( q = 458 \, \text{J} \)We can rearrange the formula to solve for \( c \):\[ c = \frac{q}{mΔT} \][/tex]
Now, plug in the given values:
[tex]- \( m = 38.2 \, \text{g} \)- \( ΔT = 46.7 \, \text{°C} - 15.4 \, \text{°C} = 31.3 \, \text{°C} \)- \( q = 458 \, \text{J} \)So, the specific heat capacity of the metal is approximately \( 0.382 \, \text{J/g°C} \).[/tex]
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