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Answer :
Final answer:
The period of rotation of Earth is 86400 seconds, its angular velocity is 7.2722 x 10^-5 radians per second, and the linear velocity at Earth's surface is approximately 464.7 meters per second.
Explanation:
Calculating Earth's Period of Rotation and Angular Velocity:
The period of rotation of the Earth is 1.00 solar day, which is equivalent to 86400 seconds. To calculate the angular velocity of Earth, we use the formula ω = 2π / T, where ω is the angular velocity and T is the period. Substituting 86400 seconds for T, we find that the angular velocity of Earth is approximately 7.2722 x 10-5 radians per second (since there are 2π radians in one rotation).
Given that Earth has a radius of 6.4×106 meters at its equator, we can calculate the linear velocity at Earth's surface with the formula v = rω, which gives us a linear velocity of approximately 464.7 meters per second.
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Rewritten by : Jeany
The angular velocity of the earth is 0.0017 rad/s.
The period of rotation of the earth in seconds can be calculated by converting one day into seconds. One day is equal to 24 hours, and each hour is equal to 60 minutes, and each minute is equal to 60 seconds. Therefore, one day is equal to 24 x 60 x 60 = 86,400 seconds. So, the period of rotation of the earth is 86,400 seconds.
To find the angular velocity of the earth, we can use the formula:
Angular velocity = 2π / time period
Substituting the values, we get:
Angular velocity = 2π / 3600 s
Angular velocity = 0.0017 rad/s
Know more about angular velocity here:
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