Thank you for visiting The energy stored in a parallel plate capacitor is 3 J What is the capacitance of the capacitor if the potential difference between the plates. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Sure, let's solve the given problem step-by-step.
Question:
The energy stored in a parallel plate capacitor is 3 Joules. What is the capacitance of the capacitor if the potential difference between the plates is 220 Volts?
Given data:
1. Energy stored (E) = 3 Joules
2. Potential difference (V) = 220 Volts
To find: Capacitance (C) in microfarads ([tex]\( \mu F \)[/tex])
Step-by-step solution:
1. Write down the formula for the energy stored in a capacitor:
[tex]\[
E = \frac{1}{2} C V^2
\][/tex]
2. Rearrange the formula to solve for capacitance (C):
[tex]\[
C = \frac{2E}{V^2}
\][/tex]
3. Substitute the given values into the formula:
[tex]\[
C = \frac{2 \times 3}{220^2}
\][/tex]
4. Calculate the capacitance in Farads:
[tex]\[
C = \frac{6}{48400} \approx 0.00012396694214876034 \, \text{Farads}
\][/tex]
5. Convert the capacitance from Farads to microfarads:
[tex]\[
1 \, \text{Farad} = 10^6 \, \mu \text{Farads}
\][/tex]
[tex]\[
C \approx 0.00012396694214876034 \, \text{Farads} \times 10^6 \approx 123.96694214876034 \, \mu \text{Farads}
\][/tex]
Result:
The capacitance of the capacitor is approximately [tex]\( 124 \, \mu F \)[/tex].
So, the correct answer is:
A. [tex]\( 124 \, \mu \text{F} \)[/tex]
Question:
The energy stored in a parallel plate capacitor is 3 Joules. What is the capacitance of the capacitor if the potential difference between the plates is 220 Volts?
Given data:
1. Energy stored (E) = 3 Joules
2. Potential difference (V) = 220 Volts
To find: Capacitance (C) in microfarads ([tex]\( \mu F \)[/tex])
Step-by-step solution:
1. Write down the formula for the energy stored in a capacitor:
[tex]\[
E = \frac{1}{2} C V^2
\][/tex]
2. Rearrange the formula to solve for capacitance (C):
[tex]\[
C = \frac{2E}{V^2}
\][/tex]
3. Substitute the given values into the formula:
[tex]\[
C = \frac{2 \times 3}{220^2}
\][/tex]
4. Calculate the capacitance in Farads:
[tex]\[
C = \frac{6}{48400} \approx 0.00012396694214876034 \, \text{Farads}
\][/tex]
5. Convert the capacitance from Farads to microfarads:
[tex]\[
1 \, \text{Farad} = 10^6 \, \mu \text{Farads}
\][/tex]
[tex]\[
C \approx 0.00012396694214876034 \, \text{Farads} \times 10^6 \approx 123.96694214876034 \, \mu \text{Farads}
\][/tex]
Result:
The capacitance of the capacitor is approximately [tex]\( 124 \, \mu F \)[/tex].
So, the correct answer is:
A. [tex]\( 124 \, \mu \text{F} \)[/tex]
Thank you for reading the article The energy stored in a parallel plate capacitor is 3 J What is the capacitance of the capacitor if the potential difference between the plates. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
