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The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:

99.5, 98.2, 98.5, 96.3, 99.8, 99.7, 98.3, 98.6

Assume body temperatures of adults are normally distributed. Based on this data, find the 80% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.

Answer :

An 80% confidence interval for the mean body temperature can be calculated by finding the sample mean and standard deviation, getting a z-value indicative of 80% confidence, and using these in the confidence interval formula. Numerical values should be rounded to three decimal places.

To find the 80% confidence interval for the mean body temperature of adults in the town, we first need to calculate the sample mean (average) and the standard deviation from the given data.

The sample mean can be calculated by adding all data points and dividing by the number of data points, while the standard deviation shows how much variation from the mean exists.

Next, we calculate the z-value associated with our desired confidence level (80%). In the standard normal distribution, an 80% confidence interval corresponds approximately to a z-value of 1.28.

The confidence interval can then be calculated using the formula: mean ± (z-value * (standard deviation / sqrt(n)), where n is the number of data points.

The numbers might then be rounded to three decimal places as instructed.

Using this method to calculate provides an understanding of where the true population mean lies with a specified level of confidence.

Learn more about Confidence Interval here:

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