Thank you for visiting A recreation center has 3 swimming pools The water level of each pool is measured each night Two of the measurements from Monday are shown. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
First, convert the mixed numbers to improper fractions.
For the first pool:
[tex]$$2 \frac{7}{12} = \frac{2 \times 12 + 7}{12} = \frac{24 + 7}{12} = \frac{31}{12}.$$[/tex]
For the second pool:
[tex]$$3 \frac{3}{8} = \frac{3 \times 8 + 3}{8} = \frac{24 + 3}{8} = \frac{27}{8}.$$[/tex]
Next, find the difference in depth by subtracting the depth of the first pool from that of the second pool:
[tex]$$\frac{27}{8} - \frac{31}{12}.$$[/tex]
To subtract fractions, convert them so they have a common denominator. The least common denominator of 8 and 12 is 24.
Convert each fraction:
[tex]$$\frac{27}{8} = \frac{27 \times 3}{8 \times 3} = \frac{81}{24},$$[/tex]
[tex]$$\frac{31}{12} = \frac{31 \times 2}{12 \times 2} = \frac{62}{24}.$$[/tex]
Now compute the difference:
[tex]$$\frac{81}{24} - \frac{62}{24} = \frac{81 - 62}{24} = \frac{19}{24}.$$[/tex]
Thus, the difference in water level depth between the second pool and the first pool is:
[tex]$$\boxed{\frac{19}{24}} \text{ feet.}$$[/tex]
For the first pool:
[tex]$$2 \frac{7}{12} = \frac{2 \times 12 + 7}{12} = \frac{24 + 7}{12} = \frac{31}{12}.$$[/tex]
For the second pool:
[tex]$$3 \frac{3}{8} = \frac{3 \times 8 + 3}{8} = \frac{24 + 3}{8} = \frac{27}{8}.$$[/tex]
Next, find the difference in depth by subtracting the depth of the first pool from that of the second pool:
[tex]$$\frac{27}{8} - \frac{31}{12}.$$[/tex]
To subtract fractions, convert them so they have a common denominator. The least common denominator of 8 and 12 is 24.
Convert each fraction:
[tex]$$\frac{27}{8} = \frac{27 \times 3}{8 \times 3} = \frac{81}{24},$$[/tex]
[tex]$$\frac{31}{12} = \frac{31 \times 2}{12 \times 2} = \frac{62}{24}.$$[/tex]
Now compute the difference:
[tex]$$\frac{81}{24} - \frac{62}{24} = \frac{81 - 62}{24} = \frac{19}{24}.$$[/tex]
Thus, the difference in water level depth between the second pool and the first pool is:
[tex]$$\boxed{\frac{19}{24}} \text{ feet.}$$[/tex]
Thank you for reading the article A recreation center has 3 swimming pools The water level of each pool is measured each night Two of the measurements from Monday are shown. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
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Rewritten by : Jeany
