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The normal boiling point of liquid methanol is 338 K. Assuming that its molar heat of vaporization is constant at 36.6 kJ/mol, what is the boiling point of CH₃OH when the external pressure is 1.29 atm?

Answer :

The Boiling point is 345.36 K at 1.332 atm.

What is boiling point?

Organic compounds' boiling points will reveal important information about their structural and physical characteristics. The boiling point of a substance aids in its identification and characterization. A liquid's boiling point is higher under higher atmospheric pressure than it is under lower atmospheric pressure.

What is vaporization ?

The process of converting a substance from its liquid or solid state into its gaseous (vapour) state is known as vaporization. Boiling is the process of vaporizing a liquid when the environment permits the development of vapor bubbles inside the liquid.

Relationship is between vapor pressure and boiling point and ΔHvap is given by clauses clampy ton.

ln ( pâ‚‚/p₁)- ΔHvap/ R ( 1/ lâ‚‚- 1/ T₁)

Now given,

normal boiling point means pressure is 1 atm

P₁= 1atm, T₁= 328k

pâ‚‚= 1,32 atm, Tâ‚‚= ?

ΔHvap= 36.6KJ/ Mol = 36600J/Mol

ln= (1.32/1) = - 36600J/mol/ 8.314 J/Mol.K (1/Tâ‚‚- 1/338K)

= 1/Tâ‚‚- 1/338K = - 6.30664*10⁻⁵ K⁻¹

= 1/Tâ‚‚ = 2.8955*10⁻³ K⁻¹

Tâ‚‚= 345.36 K

Therefore, Boiling point is 345.36 K at 1.332 atm.

Learn more about boiling point from the given link.

https://brainly.com/question/1530966

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