Thank you for visiting Determine the mass of NaOH that is necessary to neutralize 1 25 L of 0 525 M Hâ ƒPOâ A 26 3 g NaOH B. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The mass of NAOH necessary to neutralize 1.25l of0.525m H3PO4 is 78.8g.
what is NAOH?
The inorganic compound NaOH is sodium hydroxide, sometimes referred to as lye and caustic soda. The sodium cations Na+ and the hydroxide anions OH make up this white solid ionic combination.
Proteins are broken down by sodium hydroxide, a very caustic base and alkali that can result in serious chemical burns and is extremely reactive with proteins at room temperature. Easily absorbing moisture and carbon dioxide from the air, it is extremely soluble in water. NaOH and nH2O are formed in a sequence.
Water solutions between 12.3 and 61.8 °C crystallize the monohydrate NaOH, H2O. This monohydrate is frequently the "sodium hydroxide" sold commercially; therefore, the anhydrous compound may not always be used when referencing it in published data.
Volume of H3PO4 =1.25l
Number of moles of H3PO4=0.525*1.25=0.66moles of H3PO4
NAOH is used to neutralize the solution.
H3PO4+3NAOH ⇒ NA3PO4+H2O
3 moles of NAOH react with one mole of H3PO3. So, the number of moles of NAOH is equal to 3 times of number of moles of H3PO4
Number of moles of NAOH= 0.66×3=1.98moles
Mass of an object= number of moles ×molar mass
=1.98×40
= 78.8g
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