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Answer :
Final answer:
The molarity of 0.850 mol of Na2S in 1.70 L of solution is calculated to be 0.50 M.
Explanation:
The subject of your question revolves around the calculation of molarity, which in chemistry represents the concentration of a solute in a solution. To calculate molarity, we need to divide the number of moles of the solute by the volume of the solution in liters. The formula is M = moles/volume. For your specific question, you want to calculate the molarity of 0.850 mol of Na2S in 1.70 L of solution. Using the formula, the calculation becomes: M = 0.850 mol / 1.70 L = 0.50 M.
For this specific scenario, where we have 0.850 moles of Na2S in a 1.70 L solution, the molarity (M) is determined by the formula M = moles/volume, resulting in a molarity of 0.50 M. This calculation allows us to precisely quantify the concentration of the solute in the given solution, a fundamental aspect of chemical analysis and reactions.
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Rewritten by : Jeany
Molarity is simply the ratio of the number of moles of a
substance over the total volume of the solution. Assuming that the addition of
0.850 moles does not change the overall volume of 1.70 L, therefore molarity is
simply:
Molarity = 0.850 moles / 1.70 L = 0.5 moles / L = 0.5 M
