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Answer :
To melt 38.2 grams of ice at 0°C, 3053.98 calories of heat are necessary, calculated by multiplying the mass of the ice by the heat of fusion for water.
The student has asked how much heat is required to melt 38.2 grams of ice at 0℃.
To find the heat necessary, we use the concept of heat of fusion, which is the amount of heat energy required to change one gram of a substance from the solid phase to the liquid phase without changing its temperature.
Given the heat of fusion of water (Hâ‚‚O) is 79.9 cal/g, we can calculate the required heat using the following formula:
Required heat (Q) = mass in grams (m) x heat of fusion (heat_fusion)
Plugging in the values:
Q = 38.2 g x 79.9 cal/g
Q = 3053.98 calories
Therefore, 3053.98 calories of heat is necessary to melt 38.2 g of ice at 0℃.
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