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Factor the expression:

[tex]\[ 16x^4 - 625 \][/tex]

Answer :

We start with the expression:

[tex]$$ 16x^4 - 625. $$[/tex]

Step 1: Recognize a Difference of Squares

Notice that both terms are perfect squares:

- [tex]$16x^4 = (4x^2)^2$[/tex]
- [tex]$625 = 25^2$[/tex]

Thus, the expression can be written as a difference of two squares:

[tex]$$ 16x^4 - 625 = (4x^2)^2 - 25^2. $$[/tex]

Using the formula for the difference of squares,

[tex]$$ a^2 - b^2 = (a - b)(a + b), $$[/tex]

with [tex]$a = 4x^2$[/tex] and [tex]$b = 25$[/tex], we have:

[tex]$$ (4x^2)^2 - 25^2 = (4x^2 - 25)(4x^2 + 25). $$[/tex]

Step 2: Factor the Difference of Squares Again

Now, focus on the first factor:

[tex]$$ 4x^2 - 25. $$[/tex]

This too is a difference of two squares since:

- [tex]$4x^2 = (2x)^2$[/tex]
- [tex]$25 = 5^2$[/tex]

Using the difference of squares formula once more:

[tex]$$ 4x^2 - 25 = (2x - 5)(2x + 5). $$[/tex]

Step 3: Write the Fully Factored Form

The second factor, [tex]$4x^2 + 25$[/tex], is a sum of squares, which does not factor further over the real numbers.

Thus, the completely factored form of the original expression is:

[tex]$$ 16x^4 - 625 = (2x - 5)(2x + 5)(4x^2 + 25). $$[/tex]

This is the final result.

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Rewritten by : Jeany