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Answer :
Answer:
(a) 0.052 seconds
(b) 640.7 m/s
Explanation:
horizontal distance, x = 33 m
vertical distance, y = 1.3 cm = 0.013 m
(a) Let the time of flight is t.
Use second equation of motion
h = ut + 1/2 at^2
0.013 = 0 + 0.5 x 9.8 x t^2
t = 0.052 seconds.
(b) Let the speed of the bullet as it emerges from the rifle is u.
Horizontal distance = horizontal velocity x time
33 = u x 0.052
u = 640.7 m/s
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Rewritten by : Jeany
