High School

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Suppose that X₁​,...,X₂₅ are normal random variables with mean 3 and standard deviation 0.2; find the probability that Xˉ is greater than 3.05.

Answer :

M is a random variable that is normally distributed with a mean of 3.05 and a standard deviation of 1.72, then the probability P(x ≤ 8.5) is 0.99923.

A random variable that is normally distributed with a mean = 3.05

A random variable that is normally distributed with a standard deviation (SD) = 1.72

Now determining the probability

P(x ≤ 8.5) = P[(M - Mean)/SD ≤ (8.5 - 3.05)/1.72

P(x ≤ 8.5) = P(Z ≤ 5.45/1.72)

P(x ≤ 8.5) = P(Z ≤ 3.17)

From the Z-table

P(x ≤ 8.5) = 0.99923

complete question:

m is a random variable that is normally distributed with a mean of 3.05 and a standard deviation of 1.72.

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