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Find the heat dissipated across a resistor with a current of 5 amperes passing through it for 1 minute. The options are:

a) 300 J
b) 600 J
c) 1800 J
d) 3600 J

Answer :

Final answer:

The power dissipated across resistors with different resistances when a current of 5 amperes passes through is

b) 600 J

Explanation:

Power dissipation in a resistor: The power dissipated in a resistor can be calculated using the formula P = I²R, where P is power, I is current, and R is resistance. Let's calculate for each option:

Given that the current (I) is 5 amperes, the time (t) is 1 minute (which needs to be converted to seconds), we can find the heat dissipated for each resistance:

a) For

⋅(300Ω)⋅(1min×60s/min)

b) For

⋅(600Ω)⋅(1min×60s/min)

c) For

⋅(1800Ω)⋅(1min×60s/min)

d) For

⋅(3600Ω)⋅(1min×60s/min)

Let's calculate each of these:

⋅(300Ω)⋅(1min×60s/min)=75,000J

⋅(600Ω)⋅(1min×60s/min)=150,000J

⋅(1800Ω)⋅(1min×60s/min)=450,000J

⋅(3600Ω)⋅(1min×60s/min)=900,000J

Therefore the power dissipated across resistors with different resistances when a current of 5 amperes passes through is

b) 600 J

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