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Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Let the temperature at 8 AM be the first sample, and the temperature at 12 AM be the second sample.

Temperature (°F) at 8 AM:
- 98.6
- 97.7
- 97.5
- 97.8
- 98.2

Temperature (°F) at 12 AM:
- 97.1
- 96.8
- 99.3
- 98.0
- 98.0

Find the values of \( \bar{d} \) and \( S_d \). In general, what does \( \bar{d} \) represent?

Answer :

The value of d represents the differences between the temperatures at 8 AM and 12 AM for each subject, and Sd represents the standard deviation of these differences.

To find the values of d and Sd (standard deviation), we need to calculate the differences between the corresponding temperatures at 8 AM and 12 AM for each subject. Let's denote the temperature at 8 AM as the first sample (x) and the temperature at 12 AM as the second sample (y).

Subject 1: d = x - y = 98.6 - 97.8 = 0.8

Subject 2: d = x - y = 97.7 - 98.2 = -0.5

Subject 3: d = x - y = 97.5 - 97.1 = 0.4

Subject 4: d = x - y = 97.8 - 96.8 = 1.0

Subject 5: d = x - y = 98.0 - 99.3 = -1.3

Next, we calculate the mean (average) of the differences:

Mean (μd) = (0.8 - 0.5 + 0.4 + 1.0 - 1.3) / 5 = 0.08

Then, we calculate the deviations of each difference from the mean:

d - μd:

0.8 - 0.08 = 0.72

-0.5 - 0.08 = -0.58

0.4 - 0.08 = 0.32

1.0 - 0.08 = 0.92

-1.3 - 0.08 = -1.38

We square each deviation:

(0.72)^2 = 0.5184

(-0.58)^2 = 0.3364

(0.32)^2 = 0.1024

(0.92)^2 = 0.8464

(-1.38)^2 = 1.9044

Next, we calculate the sum of squared deviations:

Σ(d - μd)^2 = 0.5184 + 0.3364 + 0.1024 + 0.8464 + 1.9044 = 3.708

Finally, we calculate the standard deviation (Sd) as the square root of the sum of squared deviations divided by (n - 1), where n is the number of samples:

Sd = sqrt(Σ(d - μd)^2 / (n - 1)) = sqrt(3.708 / (5 - 1)) = sqrt(3.708 / 4) = sqrt(0.927) ≈ 0.962

Therefore, the value of d represents the differences between the temperatures at 8 AM and 12 AM for each subject, and Sd represents the standard deviation of these differences.

Learn more about deviation here:

https://brainly.com/question/31835352

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Rewritten by : Jeany