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Factor completely: [tex]x^4 - 625y^4[/tex]

Answer :

To factor the expression [tex]\(x^4 - 625y^4\)[/tex] completely, we can use the difference of squares method. Here's a step-by-step guide to solving it:

1. Recognize the structure of the expression:

The expression [tex]\(x^4 - 625y^4\)[/tex] is a difference of squares. It can be rewritten as:
[tex]\[
x^4 - (25y^2)^2
\][/tex]
Here, [tex]\(x^4\)[/tex] is [tex]\( (x^2)^2 \)[/tex] and [tex]\(625y^4\)[/tex] is [tex]\((25y^2)^2\)[/tex].

2. Apply the difference of squares formula:

The difference of squares formula is:
[tex]\[
a^2 - b^2 = (a - b)(a + b)
\][/tex]
Applying this formula, we get:
[tex]\[
x^4 - (25y^2)^2 = (x^2 - 25y^2)(x^2 + 25y^2)
\][/tex]

3. Further factor the first term, [tex]\(x^2 - 25y^2\)[/tex]:

Notice that [tex]\(x^2 - 25y^2\)[/tex] is also a difference of squares:
[tex]\[
x^2 - (5y)^2
\][/tex]
Again, using the difference of squares formula, we have:
[tex]\[
x^2 - 25y^2 = (x - 5y)(x + 5y)
\][/tex]

4. Combine all parts to get the fully factored form:

Substitute the factored form of [tex]\(x^2 - 25y^2\)[/tex] back into the expression:
[tex]\[
x^4 - 625y^4 = (x - 5y)(x + 5y)(x^2 + 25y^2)
\][/tex]

So, the completely factored form of the expression [tex]\(x^4 - 625y^4\)[/tex] is:
[tex]\[
(x - 5y)(x + 5y)(x^2 + 25y^2)
\][/tex]

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Rewritten by : Jeany