Thank you for visiting A 25 0 mL sample of an tex text H 2 text SO 4 tex solution requires 38 2 mL of a 0 163 M. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The molarity of the H2SO4 solution is 0.1245 M.
A solution of H2SO4 is neutralized by a 0.163 M NaOH solution when 38.2 mL of NaOH solution are added to a 25.0 mL H2SO4 solution. The balanced chemical equation for the reaction is:H2SO4 + 2NaOH → Na2SO4 + 2H2OTo determine the molarity of H2SO4, you need to use the stoichiometry of the balanced chemical equation. The balanced equation shows that 2 moles of NaOH react with 1 mole of H2SO4.
Therefore, the number of moles of NaOH used in the reaction is: moles NaOH = Molarity × Volume = 0.163 M × 0.0382 L = 0.0062266 mol Since 2 moles of NaOH reacts with 1 mole of H2SO4, then the number of moles of H2SO4 in the solution is :moles H2SO4 = 0.0062266 mol ÷ 2 = 0.0031133 mol The molarity of the H2SO4 solution is then calculated as follows: Molarity = moles ÷ volume Molarity = 0.0031133 mol ÷ 0.0250 L = 0.1245 M
Therefore, the molarity of the H2SO4 solution is 0.1245 M.
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