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Answer :
Final answer:
The average latency for a hard disk rotating at 3600 rpm is approximately 8.33 milliseconds. Without a transfer rate or sector size, the average transfer time for 10 sectors cannot be precisely calculated.
Explanation:
To calculate the average latency for a hard disk rotating at 3600 revolutions per minute (rpm), we must understand that latency refers to the time delay before a transfer of data begins following an instruction. The disk completes a single revolution in 1/60 seconds, since it is rotating at 60 revolutions per second (3600 rpm). Since the average latency is half the time of one full revolution (as the data can be anywhere on the disk), we divide 1/60 by 2 to get 1/120 seconds or approximately 8.33 milliseconds.
For the average transfer time of 10 sectors, we should consider the transfer rate of the disk. Unfortunately, without the transfer rate or the size of each sector, we cannot calculate this value accurately. However, if we assume a typical sector size and have the transfer rate, we would divide the total size of 10 sectors by the transfer rate to obtain the average transfer time.
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