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Answer :
Final answer:
The specific heat of lead, calculated using the formula c = q / (mΔT), is found to be 0.133 J/g°C when it takes 97.8 J to raise the temperature of a 75.0 g block by 9.80°C.
Explanation:
The question asks for the specific heat of lead. The specific heat can be calculated using the formula q = mcΔT, where q is the heat added, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
In this case, we have:
- q = 97.8 J (heat added)
- m = 75.0 g (mass of lead)
- ΔT = 9.80°C (change in temperature)
Now we need to rearrange the formula to solve for c (specific heat):
c = q / (mΔT)
Plugging in the values we get:
c = 97.8 J / (75.0 g × 9.80°C)
After calculation:
c = 0.133 J/g°C
Therefore, the specific heat of lead is 0.133 J/g°C.
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