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How many atoms are in 6.03 mol of cobalt?
6.03 mol = __________ atoms

How many moles are in [tex]1.70 \times 10^{24}[/tex] atoms of fluorine?
[tex]1.70 \times 10^{24}[/tex] atoms = __________ mol

Answer :

Final answer:

There are approximately 3.63 x 10^24 atoms in 6.03 mol of cobalt. There are approximately 2.82 mol in 1.70 x 10^24 atoms of fluorine.

Explanation:

To calculate the number of atoms in 6.03 mol of cobalt, we can use Avogadro's number. Avogadro's number is a constant that represents the number of atoms in one mole of a substance. It is approximately 6.022 x 10^23 atoms per mole.

To find the number of atoms, we can multiply the given number of moles by Avogadro's number:

Number of atoms = 6.03 mol x (6.022 x 10^23 atoms/mol)

Calculating this, we get:

Number of atoms = 3.63 x 10^24 atoms

Therefore, there are approximately 3.63 x 10^24 atoms in 6.03 mol of cobalt.

Similarly, to calculate the number of moles in 1.70 x 10^24 atoms of fluorine, we can use the same formula:

Number of moles = 1.70 x 10^24 atoms / (6.022 x 10^23 atoms/mol)

Calculating this, we get:

Number of moles = 2.82 mol

Therefore, there are approximately 2.82 mol in 1.70 x 10^24 atoms of fluorine.

Learn more about calculating the number of atoms from moles here:

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