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Answer :
Final answer:
The total energy required to remove both electrons from a neutral helium atom is the sum of the first and second ionization energies, which is 79.01 eV. Hence, the answer is D. 79 eV.
Explanation:
The energy required to remove one of the electrons from a neutral helium atom is 24.6 eV. To remove both electrons from a neutral helium atom, the total energy required is the sum of the first ionization energy plus the second ionization energy. The first ionization energy, Iâ‚, is 24.59 eV, and the second ionization energy, Iâ‚‚, is 54.42 eV. Thus, the total energy required to remove both electrons would be Iâ‚ + Iâ‚‚ = 24.59 eV + 54.42 eV = 79.01 eV. Therefore, the correct answer is D. 79 eV.
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