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Given the function [tex]f(x) = 4|x-5| + 3[/tex], for what values of [tex]x[/tex] is [tex]f(x) = 15[/tex]?

A. [tex]x = 2, x = 8[/tex]
B. [tex]x = 1.5, x = 8[/tex]
C. [tex]x = 2, x = 7.5[/tex]
D. [tex]x = 0.5, x = 7.5[/tex]

Answer :

To solve the equation [tex]\( f(x) = 4|x-5| + 3 = 15 \)[/tex] for [tex]\( x \)[/tex], follow these steps:

1. Set up the equation: Start with the function given:
[tex]\[
f(x) = 4|x-5| + 3
\][/tex]
We want to find when [tex]\( f(x) = 15 \)[/tex].

2. Subtract 3 from both sides:
[tex]\[
4|x-5| + 3 = 15
\][/tex]
Subtract 3 from both sides to isolate the absolute value term:
[tex]\[
4|x-5| = 12
\][/tex]

3. Divide by 4:
Divide both sides by 4 to further simplify:
[tex]\[
|x-5| = 3
\][/tex]

4. Set up two equations: The equation [tex]\( |x-5| = 3 \)[/tex] can be split into two separate equations to remove the absolute value:
- First equation:
[tex]\[
x - 5 = 3
\][/tex]
- Second equation:
[tex]\[
x - 5 = -3
\][/tex]

5. Solve the first equation:
- Add 5 to both sides:
[tex]\[
x = 8
\][/tex]

6. Solve the second equation:
- Add 5 to both sides:
[tex]\[
x = 2
\][/tex]

The values of [tex]\( x \)[/tex] that make [tex]\( f(x) = 15 \)[/tex] are [tex]\( x = 8 \)[/tex] and [tex]\( x = 2 \)[/tex].

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Rewritten by : Jeany