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A patient’s temperature for five days after surgery taken at 7 AM each morning was recorded as 100.8, 101.2, 100.9, 100.2, and 99.8. Which of the following was the patient’s average temperature after surgery?

A patient s temperature for five days after surgery taken at 7 AM each morning was recorded as 100 8 101 2 100 9 100

Answer :

Given:

[tex]100.8,101.2,100.9,100.2\text{ and 99.8}[/tex][tex]\begin{gathered} \text{Average}=\frac{100.8+101.2+100.9+100.2+99.8}{2} \\ =\frac{502.9}{5} \\ =100.58 \end{gathered}[/tex]

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