Thank you for visiting A 4 22 mol sample of Ar has a pressure of 1 21 atm and a temperature of 34 C What is its volume A. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
We can use the ideal gas law equation to get the volume of the sample:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
The temperature must first be converted from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 34 + 273.15 = 307.15 K
The values ​​can now be entered into the ideal gas law equation as follows:
1.21 atm * V = 4.22 mol * 0.0821 L·atm/mol·K * 307.15 K
Simplifying the equation:
V = (4.22 mol * 0.0821 L·atm/mol·K * 307.15 K) / 1.21 atm
V = 87.886 L
The volume is roughly 87.9 L, rounded to three significant numbers.
Therefore, the correct option is A.
Learn more about ideal gas law equation, here:
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