Thank you for visiting A balloon contains 38 2 g of tex H 2 tex gas at a volume of 482 L What is the volume of the gas. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
We need to use the gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.
First, we need to find the number of moles of gas in the balloon. We can do this using the formula:
n = m/M
where n is the number of moles, m is the mass of the gas (38.2g in this case), and M is the molar mass of the gas (2.016 g/mol for H2).
n = 38.2g / 2.016 g/mol = 18.95 mol
Now we can use the gas law equation to find the initial volume of the gas:
PV = nRT
V = nRT/P
where P is the pressure of the gas (which we don't know, but we can assume it's constant), T is the temperature (which
we also don't know, but we can assume it's constant), and R is the gas constant (0.0821 L·atm/mol·K).
V = (18.95 mol)(0.0821 L·atm/mol·K)(T/P)
Next, we need to find the volume of the gas when 10.0g is left out. To do this, we need to find the new number of moles of gas:
n' = (m - 10.0g)/M
n' = (38.2g - 10.0g) / 2.016 g/mol = 14.89 mol
Finally, we can use the gas law equation again to find the new volume of the gas:
V' = n'RT/P
V' = (14.89 mol)(0.0821 L·atm/mol·K)(T/P)
So the answer to the question is the difference between the initial volume and the new volume:
Volume of gas left out = V - V' = (18.95 mol)(0.0821 L·atm/mol·K)(T/P) - (14.89 mol)(0.0821 L·atm/mol·K)(T/P)
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