Thank you for visiting How much more kinetic energy does a 6 kilogram bowling ball have when it is rolling at 16 mph 7 1 meters per second than. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Sure! To find out how much more kinetic energy a 6-kilogram bowling ball has when rolling at 16 mph compared to 14 mph, we can use the kinetic energy formula:
[tex]\[ KE = \frac{1}{2} m v^2, \][/tex]
where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.
Step 1: Calculate the kinetic energy at 16 mph
Given:
- Mass [tex]\( m = 6 \)[/tex] kg
- Velocity [tex]\( v_1 = 7.1 \)[/tex] m/s (conversion of 16 mph to meters per second)
Substitute these values into the kinetic energy formula:
[tex]\[ KE_1 = \frac{1}{2} \times 6 \times (7.1)^2. \][/tex]
Perform the calculation:
[tex]\[ KE_1 = 3 \times 50.41 = 151.23 \text{ J}. \][/tex]
Step 2: Calculate the kinetic energy at 14 mph
Given:
- Velocity [tex]\( v_2 = 6.2 \)[/tex] m/s (conversion of 14 mph to meters per second)
Substitute these values into the kinetic energy formula:
[tex]\[ KE_2 = \frac{1}{2} \times 6 \times (6.2)^2. \][/tex]
Perform the calculation:
[tex]\[ KE_2 = 3 \times 38.44 = 115.32 \text{ J}. \][/tex]
Step 3: Find the difference in kinetic energy
Now, subtract the kinetic energy at 14 mph from the kinetic energy at 16 mph:
[tex]\[ KE_{\text{difference}} = KE_1 - KE_2. \][/tex]
[tex]\[ KE_{\text{difference}} = 151.23 \text{ J} - 115.32 \text{ J} = 35.9 \text{ J}. \][/tex]
Thus, the bowling ball has 35.9 joules more kinetic energy when rolling at 16 mph compared to 14 mph. The correct answer is 35.9 J.
[tex]\[ KE = \frac{1}{2} m v^2, \][/tex]
where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.
Step 1: Calculate the kinetic energy at 16 mph
Given:
- Mass [tex]\( m = 6 \)[/tex] kg
- Velocity [tex]\( v_1 = 7.1 \)[/tex] m/s (conversion of 16 mph to meters per second)
Substitute these values into the kinetic energy formula:
[tex]\[ KE_1 = \frac{1}{2} \times 6 \times (7.1)^2. \][/tex]
Perform the calculation:
[tex]\[ KE_1 = 3 \times 50.41 = 151.23 \text{ J}. \][/tex]
Step 2: Calculate the kinetic energy at 14 mph
Given:
- Velocity [tex]\( v_2 = 6.2 \)[/tex] m/s (conversion of 14 mph to meters per second)
Substitute these values into the kinetic energy formula:
[tex]\[ KE_2 = \frac{1}{2} \times 6 \times (6.2)^2. \][/tex]
Perform the calculation:
[tex]\[ KE_2 = 3 \times 38.44 = 115.32 \text{ J}. \][/tex]
Step 3: Find the difference in kinetic energy
Now, subtract the kinetic energy at 14 mph from the kinetic energy at 16 mph:
[tex]\[ KE_{\text{difference}} = KE_1 - KE_2. \][/tex]
[tex]\[ KE_{\text{difference}} = 151.23 \text{ J} - 115.32 \text{ J} = 35.9 \text{ J}. \][/tex]
Thus, the bowling ball has 35.9 joules more kinetic energy when rolling at 16 mph compared to 14 mph. The correct answer is 35.9 J.
Thank you for reading the article How much more kinetic energy does a 6 kilogram bowling ball have when it is rolling at 16 mph 7 1 meters per second than. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
