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What volume will 35.9 g of hydrogen gas (Hâ‚‚) occupy at STP?

F. 399 L
G. 798 L
H. 804 L
J. 1,620 L

Answer :

Final answer:

The volume that 35.9 g of hydrogen gas will occupy at STP is approximately 804 L.


Explanation:

To find the volume of hydrogen gas at STP, we can use the ideal gas law.

The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

At STP (standard temperature and pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).

We can rearrange the ideal gas law to solve for volume: V = nRT/P.

To find the number of moles of hydrogen gas, we can use the molar mass of hydrogen (Hâ‚‚), which is 2 grams per mole (g/mol).

Given that we have 35.9 grams of hydrogen gas, we can calculate the number of moles using the formula: moles = mass/molar mass. Therefore, the number of moles of hydrogen gas is 35.9 g / 2 g/mol = 17.95 moles.

Now we can substitute the values into the volume formula: V = (17.95 moles * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm. Calculating this gives us a volume of approximately 804 L.


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