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Answer :
To find out how many grams a 1.70 mole sample of Fe₂O₃ weighs, follow these steps:
1. Find the molar masses of the elements:
- Iron (Fe): The molar mass of iron is 55.845 grams per mole.
- Oxygen (O): The molar mass of oxygen is 15.999 grams per mole.
2. Calculate the molar mass of Fe₂O₃:
- Fe₂O₃ is composed of 2 iron atoms and 3 oxygen atoms.
- The molar mass of Fe₂O₃ can be calculated as follows:
[tex]\[
\text{Molar mass of Fe₂O₃} = (2 \times 55.845) + (3 \times 15.999)
\][/tex]
3. Molar mass calculation:
- For the two iron atoms: [tex]\(2 \times 55.845 = 111.69\)[/tex]
- For the three oxygen atoms: [tex]\(3 \times 15.999 = 47.997\)[/tex]
- Sum these values to get the total molar mass of Fe₂O₃:
[tex]\[
111.69 + 47.997 = 159.687 \text{ grams per mole}
\][/tex]
4. Calculate the weight of the sample:
- Using the calculated molar mass, find the weight of a 1.70 mole sample:
[tex]\[
\text{Weight in grams} = 1.70 \, \text{moles} \times 159.687 \, \text{grams/mole}
\][/tex]
5. Compute the final weight:
- Multiply the moles by the molar mass:
[tex]\[
1.70 \times 159.687 = 271.4679 \text{ grams}
\][/tex]
Therefore, a 1.70 mole sample of Fe₂O₃ weighs approximately 271.4679 grams.
1. Find the molar masses of the elements:
- Iron (Fe): The molar mass of iron is 55.845 grams per mole.
- Oxygen (O): The molar mass of oxygen is 15.999 grams per mole.
2. Calculate the molar mass of Fe₂O₃:
- Fe₂O₃ is composed of 2 iron atoms and 3 oxygen atoms.
- The molar mass of Fe₂O₃ can be calculated as follows:
[tex]\[
\text{Molar mass of Fe₂O₃} = (2 \times 55.845) + (3 \times 15.999)
\][/tex]
3. Molar mass calculation:
- For the two iron atoms: [tex]\(2 \times 55.845 = 111.69\)[/tex]
- For the three oxygen atoms: [tex]\(3 \times 15.999 = 47.997\)[/tex]
- Sum these values to get the total molar mass of Fe₂O₃:
[tex]\[
111.69 + 47.997 = 159.687 \text{ grams per mole}
\][/tex]
4. Calculate the weight of the sample:
- Using the calculated molar mass, find the weight of a 1.70 mole sample:
[tex]\[
\text{Weight in grams} = 1.70 \, \text{moles} \times 159.687 \, \text{grams/mole}
\][/tex]
5. Compute the final weight:
- Multiply the moles by the molar mass:
[tex]\[
1.70 \times 159.687 = 271.4679 \text{ grams}
\][/tex]
Therefore, a 1.70 mole sample of Fe₂O₃ weighs approximately 271.4679 grams.
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