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Here is a random sample of the body temperature of 25 young adults:
96.7, 96.9, 96.9, 97.2, 97.4, 97.5, 97.5, 97.6, 97.6, 97.7, 97.7, 97.8, 97.8, 97.8, 97.8, 97.8, 97.9, 98.0, 98.0, 98.1, 98.2, 98.2, 98.2, 98.4, 98.5.

Complete the relative frequency distribution table.

| Temperature Group | Frequency | Relative Frequency |
|-----------------------|-----------|--------------------|
| 96.7 ≤ x < 96.96 | 3 | 3/25 |
| 96.96 ≤ x < 97.22 | 1 | 1/25 |
| 97.22 ≤ x < 97.48 | 1 | 1/25 |
| 97.48 ≤ x < 97.74 | 6 | 6/25 |
| 97.74 ≤ x < 98.0 | 8 | 8/25 |
| 98.0 ≤ x < 98.26 | 4 | 4/25 |
| 98.26 ≤ x < 98.52 | 2 | 2/25 |

Complete the cumulative frequency and relative frequency for the table.

Answer :

Final answer:

To complete the relative frequency distribution table for body temperatures, divide the frequency of each temperature group by the total number of observations (25) and express it as a fraction or a decimal.

Explanation:

The question involves creating a relative frequency distribution table for a set of body temperatures of young adults. We already have the frequency for each temperature group, so to find the relative frequency, we divide the frequency by the total number of observations, which is 25. Then, we express each relative frequency as a fraction. For example, for the group 96.7 ≤ x < 96.96, there are 3 observations, so the relative frequency is 3/25 or 0.12 after doing the calculation. This process is repeated for each temperature group to complete the table.

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Rewritten by : Jeany