Thank you for visiting Calculate the half life in s of a first order reaction if the concentration of the reactant is 0 0576 M 17 1 s after. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Answer:
66.7s
Explanation:
Let's bring out the parameters we were given...
Half life = ?
Initial Concentration = 0.0576 M
Final Concentration = 0.0249 M
Time for the concentration change to occur = 97.8s - 17.1s = 80.7s
Formular for half life (t1/2) is given as;
t1/2 = ln2 / k ā 0.693 / k
where k = rate constant
From the formular of first order reactions;
ln[A] = ln[A]o ā kt
where [A] = Final Concentration and [A]o = Initial Concentration
Inserting the values, we have;
ln(0.0249) = ln(0.0576) - k(80.7)
Upon solving for k, we have;
-0.8387 = -k(80.7)
k = 0.01039 sā1
t1/2 = 0.693 / k = 0.693 / 0.01039 = 66.7s
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