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To what potential should you charge a 0.600 [tex]\mu\text{F}[/tex] capacitor to store 1.70 [tex]\text{J}[/tex] of energy?

Answer :

Final answer:

To store 1.70 J of energy in a 0.600 µF capacitor, you would need to charge it to a potential of approximately 5.89 V.

Explanation:

The potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2,

where U is the energy stored, C is the capacitance of the capacitor, and V is the potential difference across the capacitor.

To find the potential difference, we can rearrange the formula:

V = √(2 * U / C),

where U is the energy we want to store and C is the capacitance of the capacitor.

Plugging in the values, we have:

V = √(2 * 1.70 J / 0.600 µF)

= 5.89 V

Therefore, you would need to charge the capacitor to a potential of approximately 5.89 volts to store 1.70 joules of energy.

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Rewritten by : Jeany