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Answer :
Final answer:
To store 1.70 J of energy in a 0.600 µF capacitor, you would need to charge it to a potential of approximately 5.89 V.
Explanation:
The potential energy stored in a capacitor is given by the formula:
U = (1/2) * C * V^2,
where U is the energy stored, C is the capacitance of the capacitor, and V is the potential difference across the capacitor.
To find the potential difference, we can rearrange the formula:
V = √(2 * U / C),
where U is the energy we want to store and C is the capacitance of the capacitor.
Plugging in the values, we have:
V = √(2 * 1.70 J / 0.600 µF)
= 5.89 V
Therefore, you would need to charge the capacitor to a potential of approximately 5.89 volts to store 1.70 joules of energy.
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