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Answer :
To find the volume of a cylinder, you can use the formula:
[tex]\[ V = \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume,
- [tex]\( r \)[/tex] is the radius of the base, and
- [tex]\( h \)[/tex] is the height of the cylinder.
In this problem, the cylinder has a diameter of 10 inches. The radius is half of the diameter, so:
[tex]\[ r = \frac{10}{2} = 5 \text{ inches} \][/tex]
The height of the cylinder is given as 20 inches.
Now, we can plug these values into the formula:
[tex]\[ V = \pi \times (5)^2 \times 20 \][/tex]
This simplifies to:
[tex]\[ V = \pi \times 25 \times 20 \][/tex]
[tex]\[ V = \pi \times 500 \][/tex]
Using the value of [tex]\(\pi \approx 3.14159\)[/tex]:
[tex]\[ V \approx 3.14159 \times 500 \][/tex]
[tex]\[ V \approx 1570.8 \text{ cubic inches} \][/tex]
Therefore, the volume of the cylinder is approximately 1,570 cubic inches. Thus, the best answer is:
OD. 1,570 cu. in.
[tex]\[ V = \pi r^2 h \][/tex]
where:
- [tex]\( V \)[/tex] is the volume,
- [tex]\( r \)[/tex] is the radius of the base, and
- [tex]\( h \)[/tex] is the height of the cylinder.
In this problem, the cylinder has a diameter of 10 inches. The radius is half of the diameter, so:
[tex]\[ r = \frac{10}{2} = 5 \text{ inches} \][/tex]
The height of the cylinder is given as 20 inches.
Now, we can plug these values into the formula:
[tex]\[ V = \pi \times (5)^2 \times 20 \][/tex]
This simplifies to:
[tex]\[ V = \pi \times 25 \times 20 \][/tex]
[tex]\[ V = \pi \times 500 \][/tex]
Using the value of [tex]\(\pi \approx 3.14159\)[/tex]:
[tex]\[ V \approx 3.14159 \times 500 \][/tex]
[tex]\[ V \approx 1570.8 \text{ cubic inches} \][/tex]
Therefore, the volume of the cylinder is approximately 1,570 cubic inches. Thus, the best answer is:
OD. 1,570 cu. in.
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Rewritten by : Jeany
