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The orbit of Eris, a dwarf planet, carries it out to a maximum distance of 97.7 AU from the Sun. Assuming an albedo of 0.8, what is the average temperature of Eris when it is farthest from the Sun?

T = ?

Answer :

The average temperature of Eris when it is farthest from the sun is 30.6 K or -242.5°C.

The average temperature of Eris when it is farthest from the sun can be calculated using the Stefan-Boltzmann Law, which relates the temperature of a planet to its distance from the sun and its albedo. The formula is as follows:

T = [(L(1 - a))/(16πσd²)]^(1/4)

Where T is the temperature, L is the luminosity of the sun, a is the albedo of the planet, σ is the Stefan-Boltzmann constant, and d is the distance from the sun.

Plugging in the given values for Eris, we get:

T = [(3.828 x 10²â¶ W)(1 - 0.8)]/(16π(5.67 x 10⁻⁸ W/m²K⁴)(97.7 AU)²)]^(1/4)

T = [(3.828 x 10²â¶ W)(0.2)]/(16π(5.67 x 10⁻⁸ W/m²K⁴)(97.7 AU)²)]^(1/4)

T = 30.6 K or -242.5°C

Learn more about Stefan-Boltzmann Law here: https://brainly.com/question/30753946.

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