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Factor [tex]$16z^4 - 625y^2$[/tex] completely.

[tex]$16z^4 - 625y^2 =$[/tex]

Answer :

To factor the expression [tex]\(16z^4 - 625y^2\)[/tex] completely, follow these steps:

1. Recognize the Structure:
The expression [tex]\(16z^4 - 625y^2\)[/tex] is a difference of squares.

2. Identify Squares:
- [tex]\(16z^4\)[/tex] can be written as [tex]\((4z^2)^2\)[/tex].
- [tex]\(625y^2\)[/tex] can be written as [tex]\((25y)^2\)[/tex].

3. Apply the Difference of Squares Formula:
The difference of squares formula is [tex]\(a^2 - b^2 = (a - b)(a + b)\)[/tex].

4. Apply to the Expression:
- Here, [tex]\(a = 4z^2\)[/tex] and [tex]\(b = 25y\)[/tex].
- Substitute into the formula:
[tex]\[
16z^4 - 625y^2 = (4z^2 - 25y)(4z^2 + 25y)
\][/tex]

5. Check Further Factorization:
Now, check if each factor, [tex]\(4z^2 - 25y\)[/tex] and [tex]\(4z^2 + 25y\)[/tex], can be factored further.

- [tex]\(4z^2 - 25y\)[/tex] and [tex]\(4z^2 + 25y\)[/tex] are not perfect squares or any special products, so they cannot be factored further over the real numbers.

6. Final Answer:
The completely factored form of [tex]\(16z^4 - 625y^2\)[/tex] is:
[tex]\[
(4z^2 - 25y)(4z^2 + 25y)
\][/tex]

That's the solution to factoring the given expression completely.

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Rewritten by : Jeany