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Determine the total heat evolved in Joules when 20.3 mL of NaOH and 20.3 mL of HCl are mixed. Each solution initially has a temperature of 26.5 degrees Celsius. Upon mixing, the highest temperature reached by the solution was graphically determined to be 38.2 degrees Celsius.

Answer :

The total heat evolved in the solution is 2066 J.

we can use the formula:

q = mcΔT

where q is the heat evolved, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature.

First, we need to calculate the mass of the solution

m = 40.6 g

Next, we need to calculate the specific heat capacity of the solution. Since we are using equal volumes of NaOH and HCl, we can assume the resulting solution is neutral (pH = 7) and has a specific heat capacity close to that of water, which is 4.184 J/g°C.

c = 4.184 J/g°C

Now we can calculate the change in temperature (ΔT):

ΔT = 38.2°C - 26.5°C = 11.7°C

Finally, we can calculate the total heat evolved (q) using the formula:

q = mcΔT = (40.6 g) (4.184 J/g°C) (11.7°C) = 2066 J

Therefore, the total heat evolved in the solution is 2066 J.

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