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A current of 35.9 A flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 58.7 cm from the wire.

Answer :

The strength of the resulting magnetic field at a distance of 58.7 cm from the wire is 3.88 × 10−5 T. The strength of the magnetic field produced by a current-carrying wire depends on the current and the distance from the wire.

The formula for calculating the magnetic field strength at a distance from the wire is: B = (μ0 * I) / (2π * r), where B is the magnetic field strength, μ0 is the permeability of free space (4π × 10−7 T·m/A), I is the current in the wire, and r is the distance from the wire.

In this case, the current in the wire is 35.9 A and the distance from the wire is 58.7 cm (or 0.587 m). Plugging these values into the formula, we get: B = (4π × 10−7 T·m/A * 35.9 A) / (2π * 0.587 m)

Simplifying this equation gives us: B = 3.88 × 10−5 T

Therefore, the strength of the resulting magnetic field at a distance of 58.7 cm from the wire is 3.88 × 10−5 T.

To know more about magnetic field, refer here:

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