How many grams of [tex]\text{NH}_3[/tex] are present in 1.70 L of 1.50 M [tex]\text{NH}_3[/tex] solution?

Question

04-11-2023
Chemistry

High School

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How many grams of [tex]\text{NH}_3[/tex] are present in 1.70 L of 1.50 M [tex]\text{NH}_3[/tex] solution?

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ricksmile ricksmile · Answer 1 · 2024-07-16T21:38:14-04:00

35.76 grams of NH3 are present in 1.70 L of 1.50 M NH3 solution. To calculate the number of grams of NH3 present in a 1.70 L of 1.50 M NH3 solution.

The following formula is used:

`Molarity = moles of solute / liters of solution`.

Therefore, to solve the question above, the first step is to calculate the number of moles of NH3 in the solution.`

Molarity = moles of solute / liters of solution

`Rearranging the equation to isolate moles of solute, we get:

`Moles of solute = Molarity x liters of solution`Substituting the values given in the question, we get:`

Moles of NH3 = 1.50 M x 1.70 L`Moles of NH3 = 2.55 moles of NH3

To find the number of grams of NH3 in the solution, we use the molar mass of NH3.

`Molar mass of NH3 = 14.01 g/mol

`The number of grams of NH3 present in the solution is:`

Number of grams of NH3 = Moles of NH3 x Molar mass of NH3`

Number of grams of NH3 = 2.55 moles x 14.01 g/mol

Number of grams of NH3 = 35.76 g

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