a rifle is aimed horizontally at a target 54 m away. the bullet hits the target 2.5 cm below the aim point. What are (a) the bullets time of flight and (b) its speed as it emerges from the rifle?

Question

15-02-2025
Physics

High School

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a rifle is aimed horizontally at a target 54 m away. the bullet hits the target 2.5 cm below the aim point. What are (a) the bullets time of flight and (b) its speed as it emerges from the rifle?

Answer :

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juliastuck juliastuck · Answer 1 · 2024-09-22T01:00:03-04:00

Final answer:

The bullet's time of flight is approximately 0.071 seconds, and its speed as it emerges from the rifle is approximately 760.56 m/s (in Projectile motion).

Explanation:

To find the time of flight, we can use the following equation of motion: h = 0.5 * g * t^2, where h is the height (here it's the vertical distance bullet has fallen, -2.5 cm or -0.025 m, use the negative sign because the bullet is falling below the aimed point), g is the acceleration due to gravity (approx. 9.81 m/s^2), and t is the time. Solving for t, we get t = sqrt((2*h) / -g) which is approximately 0.071 s.

For the bullet's speed as it emerges from the rifle, we can use the formula for speed which is distance/time. This gives us the speed = distance/time = 54m/0.071s which is approximately 760.56 m/s.

Learn more about Projectile motion here:

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