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Given the function [tex]f(x)=4|x-5|+3[/tex], for what values of [tex]x[/tex] is [tex]f(x)=15[/tex]?

A. [tex]x=2, x=8[/tex]
B. [tex]x=1.5, x=8[/tex]
C. [tex]x=2, x=7.5[/tex]
D. [tex]x=0.5, x=7.5[/tex]

Answer :

To solve the problem of finding the values of [tex]\( x \)[/tex] for which the function [tex]\( f(x) = 4|x-5| + 3 \)[/tex] equals 15, we can follow these steps:

1. Set up the equation: Start with the equation of the function set equal to 15:
[tex]\[
4|x-5| + 3 = 15
\][/tex]

2. Isolate the absolute value expression: Subtract 3 from both sides to get:
[tex]\[
4|x-5| = 12
\][/tex]

3. Solve for the absolute value: Divide both sides by 4:
[tex]\[
|x-5| = 3
\][/tex]

4. Consider the two cases of the absolute value equation: The equation [tex]\(|x-5| = 3\)[/tex] results in two possible equations:
- Case 1: [tex]\(x - 5 = 3\)[/tex]
- Case 2: [tex]\(x - 5 = -3\)[/tex]

5. Solve each case:
- For the first case [tex]\(x - 5 = 3\)[/tex]:
[tex]\[
x = 3 + 5 = 8
\][/tex]
- For the second case [tex]\(x - 5 = -3\)[/tex]:
[tex]\[
x = -3 + 5 = 2
\][/tex]

Therefore, the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 15 \)[/tex] are [tex]\( x = 8 \)[/tex] and [tex]\( x = 2 \)[/tex].

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Rewritten by : Jeany

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