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Answer :
Final answer:
There are approximately 1.826 moles in 625 grams of aluminum sulfate (Al₂(SO₄)₃).
Explanation:
To calculate the number of moles in 625 grams of aluminum sulfate (Al₂(SO₄)₃), we need to follow these steps:
- Calculate the molar mass of aluminum sulfate (Al₂(SO₄)₃).
- Use the formula Moles = Mass (g) / Molar Mass (g/mol) to calculate the number of moles.
Step 1: Calculate the molar mass of aluminum sulfate (Al₂(SO₄)₃):
- Aluminum (Al) has a molar mass of 26.98 g/mol.
- Sulfur (S) has a molar mass of 32.07 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
Aluminum sulfate (Al₂(SO₄)₃) contains 2 aluminum atoms, 3 sulfur atoms, and 12 oxygen atoms.
Molar mass of aluminum sulfate (Al₂(SO₄)₃) = (2 * molar mass of aluminum) + (3 * molar mass of sulfur) + (12 * molar mass of oxygen)
= (2 * 26.98 g/mol) + (3 * 32.07 g/mol) + (12 * 16.00 g/mol)
= 342.15 g/mol
Step 2: Calculate the number of moles:
Moles = Mass (g) / Molar Mass (g/mol)
Moles = 625 g / 342.15 g/mol
Moles ≈ 1.826 moles
Learn more about calculating moles from mass here:
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