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A soup can has a height of 4 inches and a radius of 2.5 inches. What's the area of paper needed to cover the lateral face of one soup can with a label?

A) [tex]$125.7 \, \text{in}^2$[/tex]
B) [tex]$15.7 \, \text{in}^2$[/tex]
C) [tex][tex]$62.8 \, \text{in}^2$[/tex][/tex]
D) [tex]$78.5 \, \text{in}^2$[/tex]

Answer :

To find the area of paper needed to cover the lateral face of a soup can with a label, we need to calculate the lateral surface area of the can. The can has a cylindrical shape, and its lateral surface area can be determined using the formula for the lateral surface area of a cylinder, which is:

[tex]\[ \text{Lateral Surface Area} = 2 \pi r h \][/tex]

where:
- [tex]\( r \)[/tex] is the radius of the base of the cylinder
- [tex]\( h \)[/tex] is the height of the cylinder
- [tex]\( \pi \)[/tex] is approximately 3.14159

Given:
- The radius of the can [tex]\( r = 2.5 \)[/tex] inches
- The height of the can [tex]\( h = 4 \)[/tex] inches

Let's plug these values into the formula:

1. Calculate the circumference of the base (which is part of the lateral surface formula):

[tex]\[ \text{Circumference} = 2 \pi r = 2 \times 3.14159 \times 2.5 \][/tex]

2. Use this circumference to find the lateral surface area:

[tex]\[ \text{Lateral Surface Area} = \text{Circumference} \times h = (2 \times 3.14159 \times 2.5) \times 4 \][/tex]

3. Performing the calculations gives:

[tex]\[ \text{Lateral Surface Area} \approx 62.8 \][/tex]

Therefore, the area of paper needed to cover the lateral face of the soup can with a label is approximately [tex]\( 62.8 \, \text{in}^2 \)[/tex].

The correct answer is:

C) [tex]\( 62.8 \, \text{in}^2 \)[/tex]

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Rewritten by : Jeany