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Answer :
Answer:
Goal 1: Produce at least 30 tons of fuel additive.
Goal 2: Produce at least 15 tons of solvent base.
Explanation:
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Rewritten by : Jeany
To formulate the goal programming model, we need to set up the objective function and the constraints based on the given information. Let's define the decision variables and the deviation variables:
Decision variables:
Let x1 = the number of tons of fuel additive produced
Let x2 = the number of tons of solvent base produced
Deviation variables (amount by which the goals are exceeded or not met):
Let d1+ = the amount by which the number of tons of fuel additive produced exceeds the target value of 30 tons
Let d1- = the amount by which the number of tons of fuel additive produced is less than the target of 30 tons
Let d2+ = the amount by which the number of tons of solvent base produced exceeds the target value of 15 tons
Let d2- = the amount by which the number of tons of solvent base is less than the target value of 15 tons
Objective function:
Since both goals are equally important, we want to minimize the total deviations from the target values. The objective function is the sum of these deviations:
Minimize: Z = d1+ + d1- + d2+ + d2-
Constraints:
Material 1 constraint: The total material 1 used in producing fuel additive and solvent base cannot exceed the available 20 tons of material 1.
2/5 * x1 + 1/2 * x2 <= 20
Material 2 constraint: The total material 2 used in producing solvent base cannot exceed the available 5 tons of material 2.
1/5 * x2 <= 5
Material 3 constraint: The total material 3 used in producing fuel additive and solvent base cannot exceed the available 21 tons of material 3.
3/5 * x1 + 3/10 * x2 <= 21
Fuel additive production goal constraint: The fuel additive production should be at least 30 tons.
x1 + d1+ - d1- = 30
Solvent base production goal constraint: The solvent base production should be at least 15 tons.
x2 + d2+ - d2- = 15
Non-negativity constraints:
x1, x2, d1+, d1-, d2+, d2- >= 0
Now we have the complete goal programming model. The objective is to minimize the total deviations (d1+, d1-, d2+, d2-) from the target values while satisfying the material constraints and the production goals. The model can be solved using standard optimization techniques such as linear programming to find the optimal production mix.
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