Thank you for visiting Select the correct answer The atomic mass of potassium is 39 1 What is the mass of tex 6 02 times 10 23 tex atoms. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to understand the concept of atomic mass and Avogadro's number.
1. Atomic Mass and Moles: The atomic mass of potassium is given as 39.1. This value means that one mole of potassium atoms, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms (Avogadro's number), has a mass of 39.1 grams.
2. Understanding Avogadro's Number: Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole of any substance. Therefore, when you have [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, you effectively have one mole of potassium.
3. Calculating the Mass: Since one mole of potassium (which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms) has a mass equal to its atomic mass in grams, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is directly equal to 39.1 grams.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams, which corresponds to option B.
1. Atomic Mass and Moles: The atomic mass of potassium is given as 39.1. This value means that one mole of potassium atoms, which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms (Avogadro's number), has a mass of 39.1 grams.
2. Understanding Avogadro's Number: Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole of any substance. Therefore, when you have [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, you effectively have one mole of potassium.
3. Calculating the Mass: Since one mole of potassium (which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms) has a mass equal to its atomic mass in grams, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is directly equal to 39.1 grams.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams, which corresponds to option B.
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