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A boy has 11 coins in dimes and quarters. Their total value is [tex]\$1.70[/tex]. How many of each does he have?

Which of the following equations could be used to solve the problem?

A. [tex]25d + 10(11-d) = 1.70[/tex]

B. [tex]d + (11-d) = 1.70[/tex]

C. [tex]0.10d + 0.25(11-d) = 1.70[/tex]

Answer :

Here's how to set up the equations and solve the problem:

1. Define variables:

Let 'd' represent the number of dimes.

Let 'q' represent the number of quarters.

2. Set up the equations:

Equation 1 (number of coins): d + q = 11 (The boy has 11 coins total)

Equation 2 (value of coins): 0.10d + 0.25q = 2.35 (The total value is $2.35; dimes are worth $0.10 each, quarters are worth $0.25 each)

3. Choose the correct set of equations:

The correct answer is A.

4. Solve the system of equations (using substitution):

Solve Equation 1 for d:

d = 11 - q

Substitute this expression for 'd' into Equation 2:

0.10(11 - q) + 0.25q = 2.35

Distribute the 0.10:

1.10 - 0.10q + 0.25q = 2.35

Combine like terms:

1.10 + 0.15q = 2.35

Subtract 1.10 from both sides:

0.15q = 1.25

Divide both sides by 0.15:

q = 8.333...

Since you can't have a fraction of a coin, this means there is an error in the problem as written. It's not possible to have 11 dimes and quarters totaling $2.35. If the total was $2.25, the solution would be d=5 and q=6. If the total was $2.50, the solution would be d=10 and q=1.Answer:

Step-by-step explanation:

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