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Owen: [tex]\angle AEB = 45^\circ[/tex]
[tex]\angle AEC[/tex] is a right angle.

Prove: [tex]EB[/tex] bisects [tex]\angle AEC[/tex].

Proof:
We are given that [tex]m\angle AEB = 45^\circ[/tex] and [tex]\angle AEC[/tex] is a right angle.
The measure of [tex]\angle AEC[/tex] is [tex]90^\circ[/tex] by the definition of a right angle.

Applying the angle addition postulate gives:
[tex]m\angle AEB + m\angle BEC = m\angle AEC[/tex]

By substitution, we have:
[tex]45^\circ + m\angle BEC = 90^\circ[/tex]

Using the subtraction property, we find:
[tex]m\angle BEC = 45^\circ[/tex]

Thus, [tex]\angle BEC \cong \angle AEB[/tex] because they have the same measure.
Since [tex]EB[/tex] divides [tex]\angle AEC[/tex] into two congruent angles, it is the angle bisector.

Answer :

Answer:

Step-by-step explanation:

Certainly, let's analyze the given proof and see if it's valid.

Given:

* m∠AEB = 45°

* ∠AEC is a right angle

To Prove:

* EB bisects ∠AEC

Proof:

1. m∠AEC = 90° (Definition of a right angle)

2. m∠AEB + m∠BEC = m∠AEC (Angle Addition Postulate)

3. 45° + m∠BEC = 90° (Substitution Property, using m∠AEB = 45°)

4. m∠BEC = 45° (Subtraction Property of Equality)

5. ∠BEC ≅ ∠AEB (Definition of Congruent Angles: Angles with the same measure)

6. EB bisects ∠AEC (Definition of Angle Bisector: A ray that divides an angle into two congruent angles)

The proof is valid.

All the steps are logically sound and follow from the definitions and properties used.

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