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Answer :
0.10x + 0.25(11 - x) = 1.70
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Rewritten by : Jeany
Translate the statements into equations. We can use 'x' for dimes and 'y' for quarters.
"A boy has 11 coins in dimes and quarters"
[tex]\sf x+y=11[/tex]
"Their value is $1.70"
[tex]\sf 0.10x+0.25y=1.70[/tex]
To solve this, we can first solve for one of the variables in the first equation, and then plug that into the second equation:
[tex]\sf x+y=11[/tex]
Subtract 'x' to both sides:
[tex]\sf y=11-x[/tex]
Now plug this value of 'y' into the second equation:
[tex]\boxed{\sf 0.10x+0.25(11-x)=1.70}[/tex]
So this equation could be used to solve the problem.
"A boy has 11 coins in dimes and quarters"
[tex]\sf x+y=11[/tex]
"Their value is $1.70"
[tex]\sf 0.10x+0.25y=1.70[/tex]
To solve this, we can first solve for one of the variables in the first equation, and then plug that into the second equation:
[tex]\sf x+y=11[/tex]
Subtract 'x' to both sides:
[tex]\sf y=11-x[/tex]
Now plug this value of 'y' into the second equation:
[tex]\boxed{\sf 0.10x+0.25(11-x)=1.70}[/tex]
So this equation could be used to solve the problem.
