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Answer :
Answer:
To determine the volume of 0.085M H2SO4 that can be prepared from 15.0 mL of 35.9M sulfuric acid, we can use the equation:
M1V1 = M2V2
where M1 and V1 are the concentration and volume of the starting solution, and M2 and V2 are the concentration and volume of the final solution.
First, we can calculate the moles of sulfuric acid in the starting solution:
moles H2SO4 = M1V1 = (35.9 mol/L) (0.0150 L) = 0.5395 mol
Next, we can use the equation to calculate the volume of 0.085M H2SO4 that can be prepared:
M1V1 = M2V2
(35.9 mol/L) (0.0150 L) = (0.085 mol/L) V2
V2 = (35.9 mol/L) (0.0150 L) / (0.085 mol/L)
V2 = 6.34 mL
Therefore, the volume of 0.085M H2SO4 that can be prepared from 15.0 mL of 35.9M sulfuric acid is 6.34 mL.
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