Thank you for visiting A small object is attached to the end of a string to form a simple pendulum The period of its harmonic motion is measured for. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The period of motion for the length 0.500 m is 1.42 s. In order to determine the period of motion for each length of the simple pendulum in the given problem, we will use the formula for the period of a simple pendulum, given as;
T = 2π√(l/g)
Where,
T = period of the motion
l = length of the pendulum
g = acceleration due to gravity (9.81 m/s²)
Here, a small object is attached to the end of a string to form a simple pendulum. The period of its harmonic motion is measured for small angular displacements and three lengths, each time clocking the motion with a stopwatch for 50 oscillations.
For lengths of 1.000 m, 0.750 m, and 0.500 m, total times of 99.8 s, 85.5 s, and 71.1 s are measured for 50 oscillations respectively.
So, let's calculate the period of motion for each length of the simple pendulum;(a) For l = 1.000 m,
Total time for 50 oscillations, T = 99.8 s
Period of motion, T = T/50T = 99.8 s/50T = 1.996 s
Now, we will plug the value of l and g into the given formula;
T = 2π√(l/g)
T = 2π√(1.000 m/9.81 m/s²)
T = 2π x 0.3185
T = 2.000 s (approx)
Therefore, the period of motion for the length 1.000 m is 2.000 s.(b) For l = 0.750 m,
Total time for 50 oscillations, T = 85.5 s
Period of motion, T = T/50
T = 85.5 s/50
T = 1.71 s
Now, we will plug the value of l and g into the given formula;
T = 2π√(l/g)T = 2π√(0.750 m/9.81 m/s²)
T = 2π x 0.2741
T = 1.72 s (approx)
Therefore, the period of motion for the length 0.750 m is 1.72 s.
(c) For l = 0.500 m,
Total time for 50 oscillations, T = 71.1 s
Period of motion, T = T/50T = 71.1 s/50T = 1.42 s
Now, we will plug the value of l and g into the given formula;
T = 2π√(l/g)
T = 2π√(0.500 m/9.81 m/s²)
T = 2π x 0.2256
T = 1.42 s
Hence, we have found the main answer to the question and have determined the period of motion for each length of the simple pendulum.
Learn more about acceleration due to gravity: https://brainly.com/question/29135987
#SPJ11
Thank you for reading the article A small object is attached to the end of a string to form a simple pendulum The period of its harmonic motion is measured for. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
