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Answer :
Final answer:
To freeze a tray of ice cubes, we need to remove the heat from the water until it reaches the freezing point and then convert it into ice. the heat required to freeze a substance is given by the equation Q = m × ΔHf, where Q is the heat, m is the mass, and ΔHf is the molar heat of fusion.
Explanation:
To freeze a tray of ice cubes, we need to remove the heat from the water until it reaches the freezing point and then convert it into ice. the heat required to freeze a substance is given by the equation Q = m × ΔHf, where Q is the heat, m is the mass, and ΔHf is the molar heat of fusion.
From the given information, the molar heat of fusion of water is 6.01 kJ/mol. We need to convert the mass of water from grams to moles before calculating the heat. the molar mass of water is approximately 18.0 g/mol, so the number of moles of water is calculated as 40.0 g ÷ 18.0 g/mol = 2.22 mol.
Therefore, the heat required to freeze the water is Q = 2.22 mol × 6.01 kJ/mol = 13.39 kJ. So, the answer to the question is b. 13.4 kJ.
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