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Answer:
x ≈ 17.67 cm
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² = 16² + 7.5² = 256 + 56.25 = 312.25 ( take the square root of both sides )
x = [tex]\sqrt{312.25}[/tex] ≈ 17.67 ( to 2 dec. places )
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Rewritten by : Jeany
The measure of hypotenuse length x would be 17.67 cm
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
|AC|² = |AB|² + |BC|²
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
Using the Pythagoras' identity in the right angled triangle.
hypotenuse² = perpendicular² + base²
x² = 16² + 7.5²
x²= 256 + 56.25
x²= 312.25
Now take the square root of both sides
x = √312.25
x = ≈ 17.67 ( to 2 dec. places )
Therefore, the measure of hypotenuse length x would be 17.67 cm
Learn more about Pythagoras theorem here:
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