Thank you for visiting A race car entering the curved part of the track drops its speed from 46 4 m s to 35 9 m s in 2. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The magnitude of the total acceleration of the race car just after it has begun to reduce its speed is 2.91 m/s².
Explanation:
To calculate the magnitude of the total acceleration of the race car, we can use the equation for centripetal acceleration:
a = v^2 / r,
where a is the acceleration, v is the velocity, and r is the radius of the curved part of the track.
First, we need to find the initial centripetal acceleration.
Using the given velocity of 46.4 m/s and radius of 302 m, the initial acceleration is:
a1 = (46.4 m/s)^2 / 302 m = 7.18 m/s2
Next, we need to find the final centripetal acceleration.
Using the given velocity of 35.9 m/s and radius of 302 m, the final acceleration is:
a2 = (35.9 m/s)^2 / 302 m = 4.27 m/s2
The magnitude of the total acceleration is the difference between the initial and final acceleration:
Total acceleration = |a1 - a2| = |7.18 m/s2 - 4.27 m/s2| = 2.91 m/s2
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Rewritten by : Jeany
